3(4x-5)^2+17=19x-8

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Solution for 3(4x-5)^2+17=19x-8 equation: 



3(4x-5)^2+17=19x-8

We move all terms to the left:

3(4x-5)^2+17-(19x-8)=0

We get rid of parentheses

3(4x-5)^2-19x+8+17=0

We add all the numbers together, and all the variables

-19x+3(4x-5)^2+25=0

We move all terms containing x to the left, all other terms to the right

-19x+3(4x-5)^2=-25

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